Textbook p9 #25:
The Prime factorisation of a number is 2^4 X 3^5 X 7^2 X 11.
Write down 3 factors of the number that are greater than 100.
(Hint: 16 X 11 = 176, which is a factor.)
2^4=16
16X11=176
3^5=243
243X11=2673
7^2=49
49X11=539
2^4 X 3^5 X 7^2 X 11=2 095 632
The 3 factors of 2 095 632 greater than 100 are 176, 2673 and 539.
2^4=16
16X11=176
3^5=243
243X11=2673
7^2=49
49X11=539
2^4 X 3^5 X 7^2 X 11=2 095 632
The 3 factors of 2 095 632 greater than 100 are 176, 2673 and 539.
Textbook p9 #26:
The Prime factorisation of two numbers are 2 X 3^2 X 7^3 X 13 and 3 X 7^2 X 13^3 X 17 .
Write down 3 common factors of the numbers.
2 X 3^2 X 7^3 X 13 =80 262
3 X 7^2 X 13^3 X 17 =5 490 303
The 3 common factors of 80 262 and 5 490 303 are 1, 3 and 7.
2 X 3^2 X 7^3 X 13 =80 262
3 X 7^2 X 13^3 X 17 =5 490 303
The 3 common factors of 80 262 and 5 490 303 are 1, 3 and 7.
Shawn
ReplyDeleteTextbook p9 #25:
Your step-by-step explanation is clear.
Just wondering... you found the factors using "11". How would you suggest to find other factors that make up the number (2 095 632)?
Textbook p9 #26:
Could you share how you arrive at the 3 factors "1, 3 and 7"?
Also notice that you multipled the factors to get the actual number... Did you make use of these numbers when finding out the common factors?